SOLUTION: please solve this one...
A man divides $10,000 in two investments, one at 10% and the other at 30%. Find how much is invested at each rate so that the two investments produce the
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Question 490508: please solve this one...
A man divides $10,000 in two investments, one at 10% and the other at 30%. Find how much is invested at each rate so that the two investments produce the same income annually.. the answer is $2,500 and $7,500.. I just need the solution thank you..
Answer by mananth(16949) (Show Source): You can put this solution on YOUR website!
Investment I 10.00% per annum ---x
Investment II 30.00% per annum ---y
x + y= 10000 ------------------------1
10.00% x + 30.00% y = $860.00
Multiply by 100
10 x -30 y = 0 --------2
Multiply (1) by -10
we get
-10 x -10 y = -100000.00
Add this to (2)
0 x -40 y = -100000
divide by -40
y = 2500 investment at 30.00%
Balance 7500 investment at 10.00%
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