SOLUTION: Joe has a collection of nickles and dimes worth \$6.20. If the number of dimes was doubled and the number of nickles was decreased by 37, the value of the coins would be \$8.85. How

Algebra ->  Customizable Word Problem Solvers  -> Coins -> SOLUTION: Joe has a collection of nickles and dimes worth \$6.20. If the number of dimes was doubled and the number of nickles was decreased by 37, the value of the coins would be \$8.85. How       Log On

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 Question 477578: Joe has a collection of nickles and dimes worth \$6.20. If the number of dimes was doubled and the number of nickles was decreased by 37, the value of the coins would be \$8.85. How many nickles and dimes does he have?Answer by ewatrrr(11171)   (Show Source): You can put this solution on YOUR website! ``` Hi, Let x and y represent the number of nickels and dimes respectively Question states***CENTS makes sense 5x + 10y = 620 5(x-7) + 10(2y) = 885 5x + 10y = 620 5x + 10(2y) = 920 -5x - 10y = -620 5x + 10(2y) = 920 10y = 300 y = 30, the number of dimes. Number of nickels is 64. CHECKING our Answer*** 5(x-7) + 10(2y) = 885 5*57 + 10*60 = 285 + 600 = 885 OR \$8.85 ```