SOLUTION: Joe has a collection of nickles and dimes worth $6.20. If the number of dimes was doubled and the number of nickles was decreased by 37, the value of the coins would be $8.85. How

Question 477578: Joe has a collection of nickles and dimes worth $6.20. If the number of dimes was doubled and the number of nickles was decreased by 37, the value of the coins would be $8.85. How many nickles and dimes does he have?
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!

 

Hi,

Let x and y represent the number of nickels and dimes respectively

Question states***CENTS makes sense

  5x + 10y = 620

5(x-7) + 10(2y) = 885



  5x + 10y = 620

  5x + 10(2y) = 920



  -5x - 10y = -620

   5x + 10(2y) = 920

           10y = 300

             y = 30, the number of dimes. Number of nickels is 64.



CHECKING our Answer***

5(x-7) + 10(2y) = 885

5*57 + 10*60 = 285 + 600 = 885 OR $8.85 

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