SOLUTION: Joe has a collection of nickels and dimes that is worth $6.05. If the number of dimes was doubled and the number of nickels was decreased by 10, the value of the coins would be $9.
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Question 464252: Joe has a collection of nickels and dimes that is worth $6.05. If the number of dimes was doubled and the number of nickels was decreased by 10, the value of the coins would be $9.85. How many nickels and dimes does he have?
Answer by jorel1380(3719) (Show Source): You can put this solution on YOUR website!
5m+10n=605
5(m-10)+2(10)n=985
5m-50+20n=985
5m+20n=1035
5m+10n=605
10n=430
n=43
m=35
Joe has 35 nickels and 43 dimes..
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