SOLUTION: Joe has a collection of nickels and dimes that is worth $6.05. If the number of dimes was doubled and the number of nickels was decreased by 10, the value of the coins would be $9.
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Question 464031: Joe has a collection of nickels and dimes that is worth $6.05. If the number of dimes was doubled and the number of nickels was decreased by 10, the value of the coins would be $9.85. How many nickels and dimes does he have?
Answer by jorel1380(3719) (Show Source): You can put this solution on YOUR website!
5n+10d=605
5(n-10)+10(2d)=985
5n-50+20d=985
5n+20d=1035
10d=1035-605=430
d=43
n=35
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