SOLUTION: Graham has some nickels, dimes, and quarters worth $3.95. He has 7 more dimes than nickels, and 3 less quarters than nickels. How many of each type of coin does Graham have. Solve
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Question 455491: Graham has some nickels, dimes, and quarters worth $3.95. He has 7 more dimes than nickels, and 3 less quarters than nickels. How many of each type of coin does Graham have. Solve algebraically.
Answer by jorel1380(3719) (Show Source): You can put this solution on YOUR website!
d=n+7
q=n-3
5n+10(n+7)+25(n-3)=395
5n+10n+70+25n-75=395
40n=400
n=10
Graham has 10 nickels, 17 dimes, and 7 quarters..
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