SOLUTION: Harold owns 36 precious coins.He wanted to divide the coins among his three children. He told one child that he wanted her to take 4/9 of the coins.He told another child that he wa

Question 442998: Harold owns 36 precious coins.He wanted to divide the coins among his three children. He told one child that he wanted her to take 4/9 of the coins.He told another child that he wanted him to take 1/6 of the coins.His children met and tried to think of how they could divide the coins according to the father's wishes.How many coins should each child get?Show your work.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Harold owns 36 precious coins.
He wanted to divide the coins among his three children.
He told one child that he wanted her to take 4/9 of the coins.
He told another child that he wanted him to take 1/6 of the coins.
His children met and tried to think of how they could divide the coins according to the father's wishes.
How many coins should each child get?
Show your work.
---
(4/9)(4/4) = 16/36 : one of the children gets 16 of the 36
----
(1/6)(6/6) = 6/36 : the other child gets 6 of the 36
----
That leaves 12 coins still to be distributed:
=======================================================
OR
============
They could be divided in a ratio of 4/9:1/6
Then (4/9)x + (1/6)x = 36
Multiply thru by 36 to get:
16x + 6x = 36^2
22x = 1296
x = 58.91
----
One child gets (4/9)(58.91) is approx 26 coins
Other child get (1/6)(58.91) is approx 10 coins
=====================================================
Now all the coins can be distributed to the two children.
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Cheers,
Stan H.

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