SOLUTION: In her purse Anita has 16 coins (nickels,dimes,and quarters), worth $2.05. She has three times as many dimes as nickels. How many of each coin does she have?

Algebra.Com
Question 437114: In her purse Anita has 16 coins (nickels,dimes,and quarters), worth $2.05. She has three times as many dimes as nickels. How many of each coin does she have?
Found 2 solutions by mananth, oberobic:
Answer by mananth(16946)   (Show Source): You can put this solution on YOUR website!
--------------value-----------numbers
nickels 5 x
dimes 10 3x
quarters 25 16-4x

Value= 205

5x+30x-100x+400 =205
-65x=-195
-65x=-195
/-65
x=3nickels, 9 dimes,4 quarters
(15+90+100)= 205 15

Answer by oberobic(2304)   (Show Source): You can put this solution on YOUR website!
With coin problems, you have to keep track of the counts of each coin denomination as well as the value. For example, let d=number of dimes. Then the value of the number of dimes = 10d. Let n=number of nickels, 5n = value of nickels. Similarly, q=number of quarters and 25q=value of the quarters.
.
We're told she has nickels, dimes, and quarters worth $2.05 or 205 cents.
5n + 10d + 25q = 205
.
We're also told she has 16 coins, so
n + d + q = 16
.
And we're told she has 3 times as many dimes as nickels:
3n = d
or
d = 3n
.
We can use simultaneous equations.
.
5n + 10d + 25q = 205
Divide by 5
n + 2d + 5q = 41
.
Substitute d = 3n in the equations
.
n + 2(3n) + 5q = 41
n + 6n + 5q = 41
7n + 5q = 41
.
n + 3n + q = 16
4n + q = 16
.
So we have two equations with two unknowns.
7n + 5q = 41
4n + q = 16
.
Multiply the second equation by 5
20n + 5q = 80
.
7n + 5q = 41
20n + 5q = 80
.
Subtract the second equation from the first.
-13n = -39
n = 3
.
Therefore d = 3n = 9
.
Therefore q = 16 - 3 -9 = 4
.
Our tentative answer is:
n = 3
d = 9
q = 4
.
Always check your answer. In this case, we have to use the "value" equation since we used the "count" equation to figure out how many quarters.
What is the total value?
3*5 = 15 cents
9*10 = 90 cents
4*25 = 100 cents
45 + 90 + 100 = 205 cents
Correct.
.
Answer: She has 3 nickels, 9 dimes, and 4 quarters.
.
Done.

RELATED QUESTIONS

Please answer this one please Linda has some dimes nickels and quarters in her purse.... (answered by stanbon)
Susan's change purse contains quarters, dimes, and nickels. She has twice as many nickels (answered by stanbon,killahzsmilez)
Mary has nothing but nickels, dimes, and quarters in her purse. There are twice as many... (answered by TimothyLamb,MathTherapy)
can you please show example for this one. Linds has some dimes, nickels,and quaters in... (answered by Alan3354)
Lillian has 14 coins in her wallet. They coins total $1.30. She has twice as many dimes... (answered by addingup)
Sara has a collection of nickels, dimes and quarters worth $30.75. she has 15 more dimes... (answered by mananth)
sally has $1.50 worth of change in her pocket-all nickels and dimes. she has three times (answered by checkley79)
Joan has $1.75 worth of change in nickels and dimes if she has three times as many... (answered by Alan3354)
A cashier has 2 times as many nickels as quarters, 15 more dimes than quarters that worth (answered by nerdybill)