SOLUTION: Mary has $2.15 in change consisting of 11 more dimes than nickels. Find the number of nickels and dimes. how do you set up this problem and solve it?
Algebra.Com
Question 428023: Mary has $2.15 in change consisting of 11 more dimes than nickels. Find the number of nickels and dimes. how do you set up this problem and solve it?
Answer by jorel1380(3719) (Show Source): You can put this solution on YOUR website!
Assuming Mary has only nickels and dimes,then:
nickels=x
dimes=x+11
5x+10(x+11)=215
15x+110=215
15x=105
x=7
x+11=18
Mary has 7 nickels, and 18 dimes..
RELATED QUESTIONS
how do you slove this: mary has $2.35 in nickels and dimes. if she has 33 cions in all,... (answered by RedemptiveMath)
Mary has $2.40 in dimes and nickels. If she has 15 more dimes than nickels, how many of... (answered by jorel1380)
Mary has $2.40 in dimes and nickels. If she has 15 more dimes than nickels, how many of... (answered by jorel1380)
Mary has $2.85 in dimes and nickels. If she has 15 more dimes than nickels, how many of... (answered by stanbon)
Max has $3.00 in change in his pocket, consisting of quarters, dimes and nickels. The... (answered by VFBundy)
Mary has $2.20 in dimes and nickels. If she has 10 more dimes than nickels, how many of... (answered by Edwin McCravy)
John has $1.85 in nickels and dimes . The number of dimes is 1 more than twice the number (answered by jorel555)
Mongo has 20 coins consisting of nickels and dimes. if the nickels were dimes and dimes... (answered by KMST)
Sue has $2.30 in dimes and nickels. If she has 11 more dimes than nickels, how many of... (answered by mananth)