Hi
49 coins. The number of quarters is two more than twice the number of dimes
Let x , (2x+2), [49 -(3x+2)] represent the number of dimes, quarters and nickels
Question states***CENTS makes sense
10x + 25(2x+2) + 5[49-(3x+2)] = 330
Solving for x
10x + 50x+ 50 + 245 -15x - 10 = 330
45x = 45
x = 1, the number of dimes, 4 Quarters and 44 Nickels
CHECKING our Answer***
10*1 + 25*4 + 5*44 = 110 + 220 = 330 or $3.30