SOLUTION: coin collector had 6 coins for sale one he price @15,16,18,19,20,31 he sold all but one of the coins to 2 people one payinng 2xs as much as the other one which coin did he ke

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Question 416972: coin collector had 6 coins for sale
one he price @15,16,18,19,20,31 he sold all but one of the coins
to 2 people one payinng 2xs as much as the other one
which coin did he keep

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
I just tried every single number that could be the one left out
First I let x = the amount one person paid and 2x =
amount other person paid. x+%2B+2x+=+3x, so the sum of
what they bought must be divisible by 3
The only way I could arrive at this is if the coin costing 20
is left out. Then 15+%2B+16+%2B+18+%2B+19+%2B+31+=+99, so if
x+%2B+2x+=+99
3x+=+99
x+=+33
1 person bought 33 worth of coins
The other bought 66 worth
15+%2B+18+=+33
and
+16+%2B+19+%2B+31+=+66+
So, he kept the coin costing 20