SOLUTION: I have a jar with 250 coins both domes and quarters totaling 39.25 how many of each coin is there

Algebra ->  Customizable Word Problem Solvers  -> Coins -> SOLUTION: I have a jar with 250 coins both domes and quarters totaling 39.25 how many of each coin is there      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 410760: I have a jar with 250 coins both domes and quarters totaling 39.25 how many of each coin is there
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
d = number of dimes
q = number of quarters
(1) d+%2B+q+=+250
(2) 10d+%2B+25q+=+3925 (in cents)
Multiply both sides of (1) by 10
and subtract (1) from (2)
(2) 10d+%2B+25q+=+3925
(1) -10d+-+10q+=+-2500
15q+=+1425
q+=+95
d+=+250+-+95
d+=+155
There are 155 dimes and 95 quarters
check answer:
(2) 10d+%2B+25q+=+3925
(2) 10%2A155+%2B+25%2A95+=+3925
1550+%2B+2375+=+3925
3925+=+3925
OK