SOLUTION: A bag contains 208 coins made up of dollars, quarters, dimes & nickels. The total equals $77.10. How many of each type of coin are in the bag?
So far I have:
a=1.0, b=0.25, c=0
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Question 363542: A bag contains 208 coins made up of dollars, quarters, dimes & nickels. The total equals $77.10. How many of each type of coin are in the bag?
So far I have:
a=1.0, b=0.25, c=0.1, d=0.05
a+b+c+d=7
a+.25b+.1c+.05d=77.10
I have the answer through trial & error of 57 dollars, 56 quarters, 27 dimes & 68 nickels but can't figure out the complete system of equations to get me there.
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Where'd the come from??
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Let X be the number of dollars, Q quarters, D dimes, and N nickels.
1.
2.
From eq. 1,
Substituting,
Since you do not have any other equations, you have a Diophantine equation in three variables.
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The procedure to solve it is not much different than trial and error so I'm not sure I'm adding much.
Here's a link to show you how to solve these type of equations if you're interested.
http://mathforum.org/library/drmath/view/61325.html
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