SOLUTION: Amber has five dollars in her purse, consistent in nickels, dimes and quarters. If she has one more quarter then dimes, and one less nickel then dimes. How many of each type of coi
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Question 35957This question is from textbook Elementary Algebra Review Fourth Edition
: Amber has five dollars in her purse, consistent in nickels, dimes and quarters. If she has one more quarter then dimes, and one less nickel then dimes. How many of each type of coin does she have?
This question is from textbook Elementary Algebra Review Fourth Edition
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
LET X= THE NUMBER OF DIMES THEN THE NUMBER OF NICKLES (X-1) AND THE NUMBER OF QUARTERS (X+1) THUS 10X+5(N-1)+25(N+1)=500 OR 10X+5N-5+25N+25=500 OR
40X=480 OR X=480/40 OR X=12 THUS THE NUMBER OF DIMES IS 12 OR $1.20 THE NUMBER OF NICKLES ID 11 OR 5*11=$.55 & THE NUMBER OF QUARTERS IS 25*13=$3.25
$1.20+$.55+$3.25=$5.00
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