SOLUTION: a person has quarters and dimes that total $2.80. The number of dimes is 7 more than the number of quarters. how many of each coin does the person have?
Algebra.Com
Question 357157: a person has quarters and dimes that total $2.80. The number of dimes is 7 more than the number of quarters. how many of each coin does the person have?
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
D=Q+7
.25Q+.10D=2.80
.25Q+.10(Q+7)=2.80
.25Q+10Q+.70=2.80
.35Q=2.80-.70
.35Q=2.10
Q=2.10/.35
Q=6 QUARTERS.
D=6+7=13 DIMES.
PROOF:
.25*6+.10*13=2.80
1.50+1.30=2.80
2.80=2.80
RELATED QUESTIONS
A person has quarters and dimes that total $2.80. The number of dimes is 7 more than the... (answered by stanbon)
A person has quarters and dimes that total $2.80. The number of dimes is 7 more than the... (answered by solver91311)
Terry has 7 more quarters than dimes and has a total of $6.80. The number of quarters and (answered by fractalier)
Max has $2.15 in dimes and quarters. The number of dimes is 2 more than 4 times the... (answered by lwsshak3)
a boy has 7 more dimes than quarters. The total value of the coins is $4.90. Find the... (answered by josmiceli)
taylor has $3.15 in dimes and quarters. the sum of dimes is 7 more than the number of... (answered by Alan3354)
Peter has been saving his loose change for several days. When he counted his quarters and (answered by ikleyn,greenestamps)
Brandon has a jar of quarters and dimes with a total value of $6.30. The number of... (answered by solver91311,greenestamps)
I have $14.80 in dimes and quarters the number of quarters is 2 less than 3tims the... (answered by Alex2dadeath)