SOLUTION: A vending machine which takes only nickles and dimes contains $4.50. The number of dimes is 5 more than twice the number of nickles. How many of each coin are there? I starte

Question 35290: A vending machine which takes only nickles and dimes contains $4.50. The number of dimes is 5 more than twice the number of nickles. How many of each coin are there?

I started with 2n + 5 = 4.50
Found 2 solutions by checkley71, narayaba:
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
BAD START VALUE OF THE DIMES IA 10(5+2N) N BEING THE NUMBER OF NICKLES.
WE ADD TO THIS VALUE 5N THE VALUE OF THE NICKLES THEN WE HAVE
10(5+2N)+5N=450 OR 50+20N+5N=450 OR 25N=400 OR N=16 SO 16*5=80 &
10(5+2*16)=10(5+32)=10*37=370 370+80=450
Answer by narayaba(40) (Show Source): You can put this solution on YOUR website!
let x denote the number of nickels present in the vending machine
the number of dimes is 5 more than twice the number of nickels
therefore the number of dimes present in the vending machine is 2x + 5
the total amount in the vending machine is $4.50 which is 450 cents
a dime is 10 cents and nickel is 5 cents
the amount from the dimes is (2x + 5)*10
the amount from nickels is x*5
(2x+5)*10 + 5*x = 450
25x + 50 = 450
25x = 400
x = 16
the number of nickels is 16
the number of dimes is 2*16 + 5 = 37
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