SOLUTION: Prob: Monica was collecting quarters and nickels in a jar. She kept track of the total value of the coins, as well as, how many coins were actually in the jar. However, she forgot

Algebra ->  Customizable Word Problem Solvers  -> Coins -> SOLUTION: Prob: Monica was collecting quarters and nickels in a jar. She kept track of the total value of the coins, as well as, how many coins were actually in the jar. However, she forgot      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 346536: Prob: Monica was collecting quarters and nickels in a jar. She kept track of the total value of the
coins, as well as, how many coins were actually in the jar. However, she forgot specifically
to track how many of each coin there is in the jar. If the total value of all the coins is $5.60
and there are 46 coins, how many nickels and quarters are in the jar?
I came up with either 17q and 25n but got $5.50 or 18q+24n and got $5.70
please help


Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Total number of coins
1.N%2BQ=46
Total value of the coins
5N%2B25Q=560
2.N%2B5Q=112
.
.
.
Subtract eq. 1 from eq. 2,
N%2B5Q-N-Q=112-46
4Q=66
Q=33%2F2
.
.
.
Yes, as you found out, something is wrong with the problem.
You cannot reach $5.60 with 46 nickels and quarters.
$5.50 or $5.70 are the closest values for 46 coins.