SOLUTION: if there is 46 coins that equals $5.60, how many quarters and nickels are there in each using only those two coins

Question 346431: if there is 46 coins that equals $5.60, how many quarters and nickels are there in each using only those two coins
Found 2 solutions by fractalier, checkley77:
Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!
Let n be the number of nickels and q be the number of quarters. Thus
n + q = 46
Then we write the "value" equation...
5n + 25q = 560
Notice that we write $5.60 as 560 cents...
Now solve the equations by multiplying the first one by five and subtracting...
5n + 25q = 560
-(5n + 5q = 230)
we get
20q = 330
and q = 16.5 quarters...not possible...
It appears that either there is no solution or you copied it incorrectly...
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
Q+N=46 OR N=46-Q
.25Q+.05N=5.60
.25Q+.05(46-Q)=5.60
.25Q+2.30-.05Q=5.60
.20Q=5.60-2.30
.20Q=3.30
Q=3.3O/.20
Q=16.5 ANS. FOR THE NUMBER OF QUARTERS
N=46-16.5=29.5 ANS. FOR THE NUMBER OF NICKELS.
PROOF:
.25*16.5+.05*29,5=5.60
4.125+1.475=5.60
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NOT A VALID COIN PROBLEM.
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