SOLUTION: 35 coins consisting of dimes & nickles. value of coins is $3.30. How many of each type does he have?
How is this problem solved?
d+n= $3.30
Algebra.Com
Question 3403: 35 coins consisting of dimes & nickles. value of coins is $3.30. How many of each type does he have?
How is this problem solved?
d+n= $3.30
Answer by drglass(89) (Show Source): You can put this solution on YOUR website!
If d is the number of dimes and n is the number of nickels, then
and
subtract n from both sides of the first equation to get and substitute d into the second equation.
Now reduce the equation:
Subtract 3.5 from either side to get
divide both sides by -0.05 to get n = 4. If we have 4 nickels, we must have 31 dimes (n + d = 35). 31 dimes is $3.10 and 4 nickels is $0.20, so the total amount is $3.30.
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