SOLUTION: Coins are to be put into 7 pockets so that each pocket contains at least one coin. At most 3 of the pockets are to contain the same number of coins, and no two of the remaining poc

SOLUTION: Coins are to be put into 7 pockets so that each pocket contains at least one coin. At most 3 of the pockets are to contain the same number of coins, and no two of the remaining poc

Algebra.Com

Question 337146: Coins are to be put into 7 pockets so that each pocket contains at least one coin. At most 3 of the pockets are to contain the same number of coins, and no two of the remaining pockets are to contain an equal number of coins. What is the least possible number of coins needed for the pockets?
(A)7
(B)13
(C)17
(D)22
(E)28

Thanks

Answer by Edwin McCravy(20064) (Show Source): You can put this solution on YOUR website!
1 + 1 + 1 + 2 + 3 + 4 + 5 = 17
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