SOLUTION: A handful of 65 coins consist of pennies, nickles, and dimes. The number of nickels is 4 less than twice the number of pennies, and there are 13 more dimes than nickles. how many c

Question 311542: A handful of 65 coins consist of pennies, nickles, and dimes. The number of nickels is 4 less than twice the number of pennies, and there are 13 more dimes than nickles. how many coins of each kind are there?

Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
n=2p-4
d=n+13 or d=(2p-4+13)
p+n+d=65
p+(2p-4)+(2p-4+13)=65
5p-4-4+13=65
5p=65+4+4-13
5p=60
p=60/5
p=12 pennies.
n=2*12-4
n=24-4=20 nickles.
d=20+13=33 dimes.
Proof:
12+20+33=65
65=65
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