SOLUTION: The St. Mark Community babecue served 250 dinners. Achilds plate cost \$3.50 and an adult plate is \$7.00. A total of \$1347.50 was collected. How many of each type of plate was serve

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 Click here to see ALL problems on Word Problems With Coins Question 309710: The St. Mark Community babecue served 250 dinners. Achilds plate cost \$3.50 and an adult plate is \$7.00. A total of \$1347.50 was collected. How many of each type of plate was served? Please show work. ThanksFound 2 solutions by alicealc, rfer:Answer by alicealc(281)   (Show Source): You can put this solution on YOUR website!child's plate = c adult's plate = a (1) c + a = 250 (2) 3.5c + 7a = 1347.50 multiply equation (1) by 7 (1) 7c + 7a = 1750 (2)3.5c+ 7a = 1347.50 ---------------------- (-) 3.5c = 402.5 c = 402.5/3.5 = 4025/35 = 115 c + a = 250 115 + a = 250 a = 250 - 115 = 135 so, child's plates reserved = 115 plates adult's plate reserved = 135 plates Answer by rfer(12662)   (Show Source): You can put this solution on YOUR website!c+a=250 c=250-a 3.5c+7a=1347.5 3.5(250-a)+7a=1347.5 875-3.5a+7a=1347.5 3.5a=472.5 a=135 adults c=250-135 c=115 children proof 3.5*115+7*135=\$ 402.5+945=\$1347.50