SOLUTION: John has 36 coins that are nickels and dimes. If the value of the coins is $2.90, how many coins of each type does he have?
Algebra.Com
Question 291106: John has 36 coins that are nickels and dimes. If the value of the coins is $2.90, how many coins of each type does he have?
Answer by brucewill(101) (Show Source): You can put this solution on YOUR website!
Let x = # of nickels
Therefore, 36 - x = # of dimes.
5x + 10(36 - x) = 290
5x + 360 - 10x = 290
-5x = -70
nickels
36-14 = 22 dimes
Check:
0.05 * 14 = 0.70; 0.10 * 22 = $2.20, Total $2.90. OK.
RELATED QUESTIONS
Bob and Regina have 36 coins that are nickels and dimes. If the value of the coins is... (answered by addingup)
teve has 35 coins consisting of dimes and nickels. if the value of the coins is $3.30,... (answered by ewatrrr)
Felix has 40 coins consisting of dimes and nickels. If the value of his coins is $3.80,... (answered by josmiceli)
jack and betty have 28 coins that are nickels and dimes if the value of the coins is... (answered by josmiceli,JBarnum)
Steve has 36 coins consisting of dimes and nickels. If the value of the coins is $3.10,... (answered by mukhopadhyay)
Steve has 36 coins consisting of dimes and nickels. If the value of the coins is $3.10,... (answered by stanbon)
a Woman has 11 coins, consisting of nickels and dimes. she has three more dimes than... (answered by josmiceli)
Paul has 35 coins consisting of dimes and nickels. The value of his coins is $3.30 How... (answered by ad_alta)
Andres has 23 coins in his pocket. The coins consist of nickels and dimes. If the value... (answered by fion23)