SOLUTION: Mike has 19 coins (nickels, dimes, and quarters) in his piggy bank with a total value of $2.35. There are two more dimes than nickels. How many of each type of cion does mike have?

Question 289014: Mike has 19 coins (nickels, dimes, and quarters) in his piggy bank with a total value of $2.35. There are two more dimes than nickels. How many of each type of cion does mike have?
Nickels=
Dimes=
Quarters=
Found 2 solutions by nyc_function, Fombitz:
Answer by nyc_function(2741) (Show Source): You can put this solution on YOUR website!
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Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
N-number of nickels, worth 5 cents each
D-number of dimes, worth 10 cents each
Q-number of quarters, worth 25 cents each
.
.
.
"Mike has 19 coins"
1.
.
.
.
"a total value of $2.35 (235 cents)"
2.
.
.
.
"two more dimes than nickels"
3.
Substitute eq. 3 into 1 and 2.
1.

We'll call this eq. 4.
4.
.
.
.
2.

We'll call this eq. 5.
5.
Now use eq. 4, to get Q in terms of N and substitute into eq. 5.
4.

5.

Now work backwards,

And finally,

6 nickels, 8 dimes, and 5 quarters.
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