SOLUTION: Paul has some 50 cents and $2 coins. The total value of the coins is $8. If there are 7 coins altogether, how many coins of each kind does he have?

Question 271027: Paul has some 50 cents and $2 coins. The total value of the coins is $8. If there are 7 coins altogether, how many coins of each kind does he have?
Found 2 solutions by drk, stanbon:
Answer by drk(1908) (Show Source): You can put this solution on YOUR website!
(i)
(ii)
step 1 - multiply (ii) by 10 to get
(iii)
step 2 - multiply (i) by -5 to get
(iv)
step 3 - add (ii) and (iv) to get
(v)
step 4 - divide by 15 to get
(vi)
This means that

-------
There are 4, 50 cent coins and 3, 2 dollar coins
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Paul has some 50 cents and $2 coins. The total value of the coins is $8. If there are 7 coins altogether, how many coins of each kind does he have?
====
Value Eq: 50f + 200t = 800 cents
Quantity Eq: f + t = 7
--------------------------------
Solve for "f"; substitute and solve for "t":
f = 7-t
---
50(7-t) + 200t = 800
350 - 50t + 200t = 800
150t = 450
t = 3 (# of $2.00 coins)
----
Since f+t = 7, f = 4 (# of 50 cent coins)
============================================
Cheers,
Stan H.
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