SOLUTION: Sophia has $15.25 worth of nickels and dimes in her piggy bank. If she has an odd number of dimes and if she has more dimes than nickels, what is the largest number of nickels that

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Question 257637: Sophia has $15.25 worth of nickels and dimes in her piggy bank. If she has an odd number of dimes and if she has more dimes than nickels, what is the largest number of nickels that she can have?
Found 2 solutions by richwmiller, Edwin McCravy:
Answer by richwmiller(17219)   (Show Source): You can put this solution on YOUR website!

Thanks Ed. Too early before coffee
Answer by Edwin McCravy(20055)   (Show Source): You can put this solution on YOUR website!

The other tutor misread and gave you the least rather than the 
largest number of nickels.


.05n + .10d = 15.25
  
   5n + 10d = 1525

divide through by 5

     n + 2d = 305
         2d = 305 - n  
   
          d > n
         2d > 2n

    305 - n > 2n
        305 > 3n
 > n

101 would be the largest number of nickels ignoring the 
requirement that we have an odd number of dimes.

2d = 305 - n
2d = 305 - 101
2d = 204
 d = 102

The answer would be 101 nickels and 102 dimes if we could
have an even number of dimes. But since we can't have an 
even number of dimes, we have to put in one more dime, 
and thus take away 2 nickels and get

99 nickels and 103 dimes. 

Edwin
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