SOLUTION: There are 15 coins consisting of nickels, dimes and quarters. Their total is $1.10. The is one less nickels than four times the dimes. How many of each coin are there? Equation n
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-> SOLUTION: There are 15 coins consisting of nickels, dimes and quarters. Their total is $1.10. The is one less nickels than four times the dimes. How many of each coin are there? Equation n
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Question 239245: There are 15 coins consisting of nickels, dimes and quarters. Their total is $1.10. The is one less nickels than four times the dimes. How many of each coin are there? Equation needed. Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! Let = number of nickels
Let = number of dimes
Let = number of quarters
given:
(1) (in cents)
(2)
There are 3 unknowns, and only 2 equations,
so it will take some extra work to solve
Substitute (2) into (1) cents
Now just use logic
There can't be 5 quarters, since that's more than
There can't be 4 quarters, since (can't have 1/2 dime)
I'll try 3 quarters (can't have 4/3 dimes)
I'll try 2 quarters (can't have 13/6 dimes)
And 1 quarter
and, since
(2)
There is 1 quarter, 3 dimes, and 11 nickels
check:
(1)
OK
