SOLUTION: There were 35 nickels, dimes, and silver dollars in the pile, and their value was $12.25. How many coins of each kind were there if there were twice as many silver dollars as nicke

Question 233465: There were 35 nickels, dimes, and silver dollars in the pile, and their value was $12.25. How many coins of each kind were there if there were twice as many silver dollars as nickels?
Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
divide 2.05 (2 dollars and a nickel) into 12.25.
12.25/2.05=5.9...
So, there can't be more than 5 nickels and since 12.25 ends in a five there can only be 1, 3 or 5 nickels.
5 seems the most likely.
5=.25
5*$2=10
12.25-20*.1=2
=12.25 with 10 dollars, 20 dimes and 5 nickels.
There is probably a more elegant way to solve this but I don't know what it is.
.
Ed
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