SOLUTION: A person has five times as many nickels as dimes. If the total face value of these coins is $4.90, how many of each type of coin does this person have?

Question 228903: A person has five times as many nickels as dimes. If the total face value of these coins is $4.90, how many of each type of coin does this person have?
Answer by drj(1380) (Show Source): You can put this solution on YOUR website!
A person has five times as many nickels as dimes. If the total face value of these coins is $4.90, how many of each type of coin does this person have?

Step 1. Let x be the number of dimes.

Step 2. Let 0.10x be the dollar value of dimes.

Step 3. Let 5x be the number of nickels.

Step 4. Let 0.05*5x=0.25x be the dollar value of nickels and since there are 5 times as many nickels as dimes.

Step 5. Then, 0.10x+.25x=4.90 be the total dollar value.

Step 6. Solving yields the following steps:

Divide 0.35 to both sides of the equation

and

Check the dollar value using the above numbers:

which is a true statement.

Step 7. ANSWER: The number of dimes is 14 and the number of nickels is 70.

I hope the above steps were helpful.

For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.

Good luck in your studies!

Respectfully,
Dr J
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