SOLUTION: how do i solve this problem... 1. Bob has 60 coins consisting of quarters and dimes. The coins combined value is
$9.45. Find out how many of each quarters and dimes Bob has. plea
Algebra.Com
Question 190626: how do i solve this problem... 1. Bob has 60 coins consisting of quarters and dimes. The coins combined value is
$9.45. Find out how many of each quarters and dimes Bob has. please show me the steps on sloving this...
Found 3 solutions by jim_thompson5910, Alan3354, nerdybill:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
"Bob has 60 coins consisting of quarters and dimes" translates to . Solve for "q" to get . Let's call this equation 1.
Also, "The coins combined value is $9.45" translates to
Now multiply EVERY term of the last equation by 100 to make every number a whole number to get: Let's call this equation 2.
-------------------------
Start with the second equation.
Plug in
Distribute.
Combine like terms on the left side.
Subtract from both sides.
Combine like terms on the right side.
Divide both sides by to isolate .
Reduce.
So there are 37 dimes
----------------------------------------------------------------------
Go back to the first equation
Plug in
Subtract
So there are 23 quarters
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
1. Bob has 60 coins consisting of quarters and dimes. The coins combined value is
$9.45. Find out how many of each quarters and dimes Bob has.
----------------------
Q + D = 60 (60 coins)
25Q + 10D = 945 (total value)
Q = 60 - D (from 1st eqn)
Sub into 2nd eqn
25*(60-D) + 10D = 945
1500 - 25D + 10D = 945
-15D = - 555
D = 37
Q = 23
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
Bob has 60 coins consisting of quarters and dimes. The coins combined value is
$9.45. Find out how many of each quarters and dimes Bob has. please show me the steps on sloving this...
.
Let d = number of dimes
then
60-d = number of quarters (since we have a total of 60 coins)
.
.10d + .25(60-d) = 9.45
.10d + 15 - .25d = 9.45
15 - .15d = 9.45
15 - .15d = 9.45
15 = 9.45 + .15d
5.55 = .15d
37 = d (number of dimes)
.
Number of quarters:
60-d = 60-37 = 23 (number of quarters)
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