SOLUTION: sandy has $3.25 in change. She has five more dimes than quarters but twice as many nickels as dimes. Express the given information as an algebraic equation and simplify.

Algebra.Com
Question 190237: sandy has $3.25 in change. She has five more dimes than quarters but twice as many nickels as dimes. Express the given information as an algebraic equation and simplify.
Answer by ankor@dixie-net.com(22740)   (Show Source): You can put this solution on YOUR website!
andy has $3.25 in change. She has five more dimes than quarters but twice as many nickels as dimes. Express the given information as an algebraic equation and simplify.
;
An equation for the total $
.05n + .10d + .25q = 3.25
:
"She has five more dimes than quarters"
d = (q + 5)
or
q = (d-5)
:
" but twice as many nickels as dimes."
n = 2d
:
Substitute for n and q in the $$ equation:
.05(2d) + .10d + .25(d-5) = 3.25
:
.10d + .10d + .25d - 1.25 = 3.25
Simplify:
.45d = 3.25 + 1.25
:
.45d = 4.50
:
They didn't say anything about solving it, but it's pretty easy now




RELATED QUESTIONS

Sandy has $3.25 in change. She has five more dimes than quarters but twice as many... (answered by solver91311)
Sandy has $3.75 in change. She has three more quarters than dimes but twice as many... (answered by jojo14344)
Sandy has $3.75 in change. She has three more quarters than dimes but twice as many... (answered by ankor@dixie-net.com)
Sandy has 3.25 in change. She has five more dimes than quarters but twice as many nickels (answered by Mathtut)
Sandy has $3.75 in change. She has 3 more quarters than dimes but twice as many nickles... (answered by jojo14344)
Sandy has $3.25 in change. She has five more dimes that quarters but twice as many... (answered by MathTherapy)
Hi. I need help answering the following question. Thanks in advance. Sandy has $3.75 in... (answered by nerdybill)
Sandy has $3.25 in change. She has five more dimes than quarters but twice as many... (answered by stanbon)
I need help with this word problem. Can anyone help me? I do appreciate whatever you can... (answered by ankor@dixie-net.com,scott8148)