SOLUTION: This is similar to a question answered by gonzo(654)and was said to be from a textbook. I have tried using the same fomula but cannot get the correct answer. Here is the question

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Question 189599: This is similar to a question answered by gonzo(654)and was said to be from a textbook. I have tried using the same fomula but cannot get the correct answer. Here is the question: Sam found a number of nickles, dimes and quarters. He found six more dimes than nickels but three times as many quarters as dimes. The total value of the coins was $11.40. How many coins of each type did Sam find? Can you help?
Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
Let n=# of nickels, d=# of dimes, and q=# of quarters


Since "He found six more dimes than nickels but three times as many quarters as dimes", this means that and . We'll call these equations 1 and 2.


Furthermore, because "The total value of the coins was $11.40", this means that


Note: the total value of the nickels alone is (ie the value of ONE nickel multiplied by the number of nickels). The same is applied to the dimes and quarters. These expressions are then added up to get the total value. This is probably where you're stuck.


Start with the last equation.


Multiply EVERY term by 100 to make every number a whole number


Multiply. Let's call this equation 3.



-----------------------------------------------------


So we have the equations


Equation 1:

Equation 2:

Equation 3:


You may see this as a system of equations, which looks like





=========================================================


Start with the third equation


Plug in . Notice how the variable "q" is no longer in the equation.





Multiply


Plug in . Now the variable "d" is gone.


Now we're left with a simple equation with one unknown variable.





Distribute.


Combine like terms on the left side.


Subtract from both sides.


Combine like terms on the right side.


Divide both sides by to isolate .


Reduce.


So this means that there are 7 nickels.


--------------------------------------------


Go back to the first equation


Plug in


Add


So there are 13 dimes


--------------------------------------------


Move onto the second equation


Plug in


Multiply


So there are 39 quarters.



========================================================

Answer:

So there are 7 nickels, 13 dimes and 39 quarters.

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