SOLUTION: There is a total of 25 coins in Nickles, Dimes, and Quarters. There are four times as many dimes as quarters. The total vaule of the change is $2.05, how many of each coin is the
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Question 176676: There is a total of 25 coins in Nickles, Dimes, and Quarters. There are four times as many dimes as quarters. The total vaule of the change is $2.05, how many of each coin is there?
I have tried a few equations:
1) 5(x-5)+10(4x)+25(x+15)=205
2) 5(x-20)+10(4x-15)+25x=205
3) 5x+10(4x)+25x+=205
I know this can be solved with multiple variables, but I am suppose to solve it with one. Please help.
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Let = number of nickels
Let = number of dimes
Let = number of quarters
given:
(1)
(2)
In pennies:
(3)
There are 3 equations and 3 unknowns, so it's solvable
Multiply (1) by and subtract from (3)
--------------------------
And using (2),
(1)
There are 15 nickels, 8 dimes and 2 quarters
check:
(3)
OK
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