# SOLUTION: Sam found a number of nickels, dimes and quarters in his room. He found 3 more dimes than nickels but twice as many quarters as dimes. The total value of the coins was \$5.05 how ma

Algebra ->  Algebra  -> Customizable Word Problem Solvers  -> Coins -> SOLUTION: Sam found a number of nickels, dimes and quarters in his room. He found 3 more dimes than nickels but twice as many quarters as dimes. The total value of the coins was \$5.05 how ma      Log On

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 Question 176671This question is from textbook : Sam found a number of nickels, dimes and quarters in his room. He found 3 more dimes than nickels but twice as many quarters as dimes. The total value of the coins was \$5.05 how many coins of each type did Sam find?This question is from textbook Answer by gonzo(654)   (Show Source): You can put this solution on YOUR website!let n = number of nickels let d = number of dimes let q = number of quarters. --- d = n+3 q = 2*d = 2*(n+3) = 2*n+6 --- since: \$5.05 * 100 = 505 cents and: 5*n = number of nickels * 5 cents per nickel 10*d = number of dimes * 10 cents per dime 25*q = number of quarters * 25 cents per quarter then: 5*n + 10*d + 25*q = 505 cents --- since d = n+3, and q = 2d = 2*n+6, then: 5*n + 10*(n+3) + 25*(2*n+6) = 505 --- remove parentheses and this equation becomes: 5*n + 10*n + 30 + 50*n + 150 = 505 combine like terms to get: 65*n + 180 = 505 subtract 180 from both sides to get: 65*n = 325 divide both sides by 65 to get: n = 5 --- number of nickels = 5 number of dimes is number of nickels + 3 = 8 number of quarters is 2 times number of dimes = 16 --- 5 nickels times 5 cents each is 25 cents 8 dimes times 10 cents each is 80 cents 16 quarters times 25 cents each is 400 cents 400 cents + 80 cents + 25 cents = 505 cents. divide 505 cents by 100 to get: \$5.05 --- answer is: sam found 5 nickels, 8 dimes, and 16 quarters. ---