SOLUTION: Joe has a collection of nickels and dimes that is worth \$5.65. If the number of dimes were doubled and the number of nickels were increased by 8, the value of the coins would be \$1

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 Click here to see ALL problems on Word Problems With Coins Question 171437: Joe has a collection of nickels and dimes that is worth \$5.65. If the number of dimes were doubled and the number of nickels were increased by 8, the value of the coins would be \$10.45. How many dimes does he have?Answer by ptaylor(2048)   (Show Source): You can put this solution on YOUR website!Let x=number of nickels y=number of dimes Lets deal in pennies: We are told that: 5x+10y=565 divide each term by 5 x+2y=113----------------------------------eq1 and 5(x+8)+10*2y=1045= 5x+40+20y=1045 subtract 40 from each side 5x+20y=1005 divide each term by 5 x+4y=201-----------------------------------------eq2 subtract eq1 from eq2: 2y=88 y=44-------------------------- number of dimes substitute into eq1: x+88=113 x=25-------------------------number of nickels CK 5*25+10*44=565 125+440=565 565=565 and 5*(25+8)+10*88=1045 165+880=1045 1045=1045 Hope this helps----ptaylor