# SOLUTION: A coin collection consists of 14 coins with a value of \$1.35. The coins are nickels, dimes, and quarters. The numbers of nickles is three less than twice the number of dimes. How m

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 Question 171118: A coin collection consists of 14 coins with a value of \$1.35. The coins are nickels, dimes, and quarters. The numbers of nickles is three less than twice the number of dimes. How many of each coin is there in the collectionAnswer by ptaylor(2048)   (Show Source): You can put this solution on YOUR website!Let x=number of nickels y=number of dimes z=number of quarters Lets deal in pennies; we are told that: 5x+10y+25z=135---------------------eq1 x+y+z=14-----------------------------eq2 and x=2y-3-------------------------------eq3 multiply eq2 by 25 (we get: 25x+25y+25z=350) and subtract eq1 from it and we get: 20x+15y=215---------------------eq2a substitute x=2y-3 from eq3 into eq2a: 20(2y-3)+15y=215 simplifying we get: 40y-60+15y=215 add 60 to each side 55y=275 divide each side by 5 y=5 -------------------------------------number of dimes From eq3: x=2y-3=2*5-3=7------------------------------number of nickels substitute x=7 and y=5 into eq2 and we get: 7+5+z=14 z=2--------------------------------------------number of quarters CK 7+5+2=14 14=14 and 7*5+10*5+2*25=135 35+50+50=135 135=135 Hope this helps---ptaylor