SOLUTION: you have one hundred coins in your coin jar, consisting of nickels, dimes and quarters. the total value of the coins is &11.80 and you have 10 more nickels than dimes. How many of
Algebra ->
Customizable Word Problem Solvers
-> Coins
-> SOLUTION: you have one hundred coins in your coin jar, consisting of nickels, dimes and quarters. the total value of the coins is &11.80 and you have 10 more nickels than dimes. How many of
Log On
Question 169935: you have one hundred coins in your coin jar, consisting of nickels, dimes and quarters. the total value of the coins is &11.80 and you have 10 more nickels than dimes. How many of each coin do you have?
x=dimes
x +10= nickels
90-2x= quarters
You can put this solution on YOUR website! you have one hundred coins in your coin jar, consisting of nickels, dimes and quarters. the total value of the coins is &11.80 and you have 10 more nickels than dimes. How many of each coin do you have?
x=dimes
x +10= nickels
90-2x= quarters
-----------------
What you have is correct.
Then add:
10*x + 5*(x+10) + 25*(90-2x) = 1180
You can do it from here, I'm sure, but...
10x + 5x+50 + 2250-50x = 1180
-35x = -1120
x = 32 dimes (= $3.20)
42 = nickels (= $2.10)
26 = quarters (= $6.50)
100 coins------$11.80