I'll just work the problem for you. You'll have to
write it up using complete sentences and proper grammar,
and filling in your own explanations.
Let p = the number of pennies
Let n = the number of nickels
Let d = the number of dimes
We have the equation:
or multiplying through by 100,
Since half the coins are nickels, we have
We have the system:
Substituting for in the first equation
Divide through by 3:
Since the left side is even,
the right side must be even also,
and positive. Therefore
must be even and positive, too,
Therefore d must be odd and no more
than 11.
Therefore there are 6 possibilities:
d = 1, 3, 5, 7, 9, or 11
If , then
becomes
Substituting and
into
So one possibility is
, ,
-------
If , then
becomes
Substituting and
into
So another possibility is
, ,
-----------------
If , then
becomes
Substituting and
into
So another possibility is
, ,
-------------
If , then
becomes
Substituting and
into
So another possibility is
, ,
-------------
If , then
becomes
Substituting and
into
So another possibility is
, ,
-------------
If , then
becomes
Substituting and
into
So another possibility is
, ,
-------------
So all the 6 possibilities are
0 pennies, 11 nickels, 11 dimes, 22 coins, half of which are 11 nickels.
5 pennies, 14 nickels, 9 dimes, 28 coins, half of which are 14 nickels.
10 pennies, 17 nickels, 7 dimes, 34 coins, half of which are 17 nickels.
15 pennies, 20 nickels, 5 dimes, 40 coins, half of which are 20 nickels.
20 pennies, 23 nickels, 3 dimes, 46 coins, half of which are 23 nickels.
25 pennies, 26 nickels, 1 dimes, 52 coins, half of which are 26 nickels.
Edwin