SOLUTION: Sandy held a garage sale during which she charged a dime for everything, but accepted a nickel if the buyer bargained well. At the end of the day she realized she had sold all 12 i

Question 153636: Sandy held a garage sale during which she charged a dime for everything, but accepted a nickel if the buyer bargained well. At the end of the day she realized she had sold all 12 items and raked in a grand total of 95 cents. She had only dimes and nickels. How many of each did she have? (please show work) Thank you so much
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Sandy held a garage sale during which she charged a dime for everything, but accepted a nickel if the buyer bargained well. At the end of the day she realized she had sold all 12 items and raked in a grand total of 95 cents. She had only dimes and nickels. How many of each did she have? (please show work) Thank you so much
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Quantity: d + n = 12
Value: 10d + 5n = 95
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Multiply the 1st equation by 10 to get:
10d + 10n = 120
10d + 5n = 95
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Subtract 2nd from 1st to get:
5n = 25
n = 5 (# of nickels)
Since d+n + 12, d= 12-5; d = 7 (# of dimes)
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Cheers,
Stan H.
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