SOLUTION: A candy shop mixes nuts worth $1.10 per pound with another variety worth $0.80 per pound in order to make 42 pounds of a mixture worth $0.90 per pound. How many pounds of each kind

Question 151812: A candy shop mixes nuts worth $1.10 per pound with another variety worth $0.80 per pound in order to make 42 pounds of a mixture worth $0.90 per pound. How many pounds of each kind of nut should be used?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
A candy shop mixes nuts worth $1.10 per pound with another variety worth $0.80 per pound in order to make 42 pounds of a mixture worth $0.90 per pound. How many pounds of each kind of nut should be used?
:
Let x = lbs of $1.10 nuts required
;
It says the total will be 42 lb, therefore:
(42-x) = lbs of $.80 nuts required
;
A typical mixture equation:
1.1x + .8(42 - x) = .9(42)
:
1.1x + 33.6 - .8x = 37.8
:
1.1x - .8x = 37.8 - 33.6
:
.3x = 4.2
x =
x = 14 lb of $1.10 nuts
Then
42 - 14 = 28 lb of $.80 nuts
;
:
Check solution in original equation:
1.1(14) + .8(28) = .9(42)
15.4 + 22.4 = 37.8; confirms our solution
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