SOLUTION: bob has four times as many nickles as quarters. he has $3.60 total. how many of each coin does he have?

Algebra ->  Customizable Word Problem Solvers  -> Coins -> SOLUTION: bob has four times as many nickles as quarters. he has $3.60 total. how many of each coin does he have?      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 14566: bob has four times as many nickles as quarters. he has $3.60 total. how many of each coin does he have?
Answer by Alwayscheerful(414) About Me  (Show Source):
You can put this solution on YOUR website!
Okay, for this question, you need two equations that you would solve with substitution or elimination.
The first equation we can derive from the first sentence.
4q=n
You can check that that equation is true by giving yourself an example. If you have 2 quarters, then you have 8 nickles. Plug it in. If it works, then it is true.
Your second equation should look like this.
.05n%2B.25q=3.6
How did I get that?
A nickel is worth 5 cents, .05 of a dollar.
A quarter is worth 25 cents, .25 of a dollar.
They both add up to become $3.6
You don't have to have the dollar signs in your equation (unless you teacher states otherwise) because it just makes it messier.
Then you have your system of equations.
4q=n
.05n%2B.25q=3.6
I would use substitution because it already has the n isolated
Just plug it in and solve.
.05%284q%29%2B.25q=3.6
Multiply and Solve
.2q%2B.25q=3.6
.45q=3.6
q=8
Since you now know the number of quarters, you have 4 times as many nickels.
The number of nickels would then be 32
You can check by multiplying.
8 quarters = $2
32 nickels = $1.60
%242%2B%241.6=%243.60
Your final answer:
8 quarters and 32 nickels
Hope this helps!