SOLUTION: I have not been able to find a formula for a coin problem with no value. The problem is: Rita has a collection of 105 coins consisting of nickels, dimes, and quarters. The number
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: I have not been able to find a formula for a coin problem with no value. The problem is: Rita has a collection of 105 coins consisting of nickels, dimes, and quarters. The number of dimes is 5 more than one-third the number of nickels, and the number of quarters is twice the number of dimes. How many coins of each kind does she have?
This question is from textbook
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
"105 coins consisting of nickels, dimes, and quarters" __ 105=n+d+q
"number of dimes is 5 more than one-third the number of nickels" __ d=5+(n/3) __ 3(d-5)=n
"number of quarters is twice the number of dimes" __ q=2d
substituting __ 105=3(d-5)+d+2d __ 120=6d __ 20=d
substituting __ 3(20-5)=n __ 45=n
substituting __ q=2(20) __ q=40
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