SOLUTION: I have six more than twice as many dimes as I have nickels. I have four less quarters than nickels. Altogether I have $5.60. How many of each coin do I have?

Question 131831: I have six more than twice as many dimes as I have nickels. I have four less quarters than nickels. Altogether I have $5.60. How many of each coin do I have?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
I have six more than twice as many dimes as I have nickels. I have four less quarters than nickels. Altogether I have $5.60. How many of each coin do I have?
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Let number of nickels be "x" ; value of these is 5x cents
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# of dimes = "2x+6" ; value is 10(2x+6) = 20x+60 cents
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# of quarters = "x-4" ;value is 25(x-4) = 25x-100 cents
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EQUATION:
value + value + value = 560cents
5x + 20x+60 + 25x-100 = 560
50x = 600
x = 12 (# of nickels)
2x+6 = 32 (# of dimes)
x-4 = 8 (# of quarters)
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Cheers,
Stan H.
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