SOLUTION: Please help me solve this problem: Austin has nickels, dimes and quarters. He has a total of $17.65. He has eleven fewer quarters than nickels and six times as many dimes as quarte

Question 12493: Please help me solve this problem: Austin has nickels, dimes and quarters. He has a total of $17.65. He has eleven fewer quarters than nickels and six times as many dimes as quarters. How many of each coin does he have?

Answer by stanbon!(97) (Show Source): You can put this solution on YOUR website!
Let number of nickels be "x".
Then number of quarters is "x-11"
And number of dimes is "6(x-11)" = "6x-66"
Value of nickels is (5)x cents
Value of quarters is (25)(x-11)= 25x-275 cents
And Value of dimes is (10)(6x-11)= 60x-110 cents
EQUATION:
Value of nickels + Value of dimes + Value of quarters = 1765 cents
5x + 25x-275 + 60x-110 = 1765
90 x = 2150
x = 23.89... (number of nickels??????)
Answer doesn't nake sense since you can't have 23.89 nickels.
Cheers,
Stan H.
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