SOLUTION: Shantel has $ 3.60 in dimes and nickles in her car. The number of nickles is three more than the number of dimes. How many of each type of coin does she have?

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Question 1204453: Shantel has
$
3.60
in dimes and nickles in her car. The number of nickles is three more than the number of dimes. How many of each type of coin does she have?
Found 3 solutions by josgarithmetic, ikleyn, greenestamps:
Answer by josgarithmetic(39630)   (Show Source): You can put this solution on YOUR website!
$3.60 in dimes and nickels



from here you could try to make a money equation in only the variable d for the dimes.

---------the rest should be clear.
Answer by ikleyn(52903)   (Show Source): You can put this solution on YOUR website!
.
Shantel has $3.60 in dimes and nickles in her car. The number of nickles
is three more than the number of dimes. How many of each type of coin does she have?
~~~~~~~~~~~~~~~~~~~~~ 

x dimes; (x+3) nickels.


Write the total money equation

    10x + 5(x+3) = 360  cents.


Simplify and find x

    10x + 5x + 15 = 360

       15x        = 360 - 15 = 345

         x                   = 345/15 = 23.


ANSWER.  23 dimes and 23+3 = 26 nickels.


CHECK.  23*10 + 26*5 = 360  cents,  in total.   ! correct !

Solved.



Answer by greenestamps(13215)   (Show Source): You can put this solution on YOUR website!


Probably a formal algebraic solution, like the one shown by tutor @ikleyn, was wanted. But you can get good mental exercise solving the problem informally, using logical reasoning and mental arithmetic.

The number of nickels is 3 more than the number of dimes, and the total value is $3.60.

Set aside those 3 "extra" nickels, worth $0.15, leaving a value of $3.45 for the remaining coins.

Those remaining coins are equal numbers of nickels and dimes. The value of one nickel and one dime is $0.15. $3.45/$0.15 = 23, so the remaining coins are 23 nickels and 23 dimes.

Now add back in the other 3 nickels, making 26 nickels and 23 dimes.

ANSWER: 26 nickels and 23 dimes
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