SOLUTION: When they counted their coins,they had 190 in all their coins were either P5 or P20 coins. If they have P2,000 from the coins,how many P5 coins were there? How about P20 coins?

Question 1204265: When they counted their coins,they had 190 in all their coins were either P5 or P20 coins. If they have P2,000 from the coins,how many P5 coins were there? How about P20 coins?
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
x = numbr of P5 coins.
y = number of P20 coins.
your 2 equations are:
x + y = 190
5x + 20y = 2000
multiply both sides of the first equation by 5 to get:
5x + 5y = 5 * 190
5x + 20y = 2000
subtract the first equation from the second to get:
15y = 2000 - 950
solve for y to get:
y = (2000 - 950) / 15 = 1050 / 15 = 70
since x + y = 190, then x = 120
they have 120 P5 coins and 70 P20 coins.
120 * P5 + 70 * P20 = P2000 confirming the number of P5 and P20 is correct.
your solution is there are 120 P5 coinjs and 70 P20 coints for a total of P2000.

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