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Roger has $2.60 in quarters and dimes. He has 14 coins altogether.
How many coins of each kind does he have?
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Q quarters; (14-Q) dimes.
Write the total money equation
25Q + 10*(14-Q) = 260 cents.
Simplify and find Q
25Q + 140 - 10Q = 260
25Q - 10Q = 260 - 140
15Q = 120
Q = 120/15 = 8.
ANSWER. 8 quarters and (14-8) = 6 dimes.
Solved.
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For introductory coin problems, look into the lessons
- Coin problems
- More Coin problems
- Solving coin problems without using equations
- Kevin and Randy Muise have a jar containing coins
- Solving coin problems mentally by grouping without using equations
in this site.
Read them attentively and become an expert in this field.