SOLUTION: How much 50% antifreeze solution and 40% antifreeze solution should be combined to give 50 gallons of 46% antifreeze solution?
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Question 1200511: How much 50% antifreeze solution and 40% antifreeze solution should be combined to give 50 gallons of 46% antifreeze solution?
Found 2 solutions by josgarithmetic, greenestamps:
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
h of the 50%
50-h of the 40%
Result Wanted, 50 gallons of 46%
, to account for amount of pure antifreeze.
---------The computations were not yet done, so you can think about the form of this expression for variable h. ....
Now, compute h, and use it to evaluate 50-h.
Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!
The response from the other tutor shows a typical setup for solving the problem using formal algebra. Assuming you are studying algebra, you should understand that method.
If formal algebra is not required and you want a fast path to the answer, you can do the following.
46% is 6/10 = 3/5 of the way from 40% to 50%.
That means 3/5 of the mixture should be the higher percentage antifreeze.
ANSWERS: 3/5 of 50 gallons, of 30 gallons, of the 50% antifreeze, the other 20 gallons of 40%
CHECK:
.50(30)+.40(20) = 15+8 = 23
.46(50) = 23
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