SOLUTION: a jar of dimes and quarters contains $15.25.there are 103 coins in all.how many of each are there?

Question 118704: a jar of dimes and quarters contains $15.25.there are 103 coins in all.how many of each are there?
Answer by ptaylor(2198) (Show Source): You can put this solution on YOUR website!

Let x=number of quarters; value of quarters=0.25x
Then 103-x=number of dimes; value of dimes=0.10(103-x)
Now we are told that the value of the quarters plus the value of the dimes equals $15.25. So our equation to solve is:
0.25x+0.10(103-x)=$15.25 get rid of parens
0.25x+10.30-0.10x=15.25 subtract 10.30 from both sides
0.25x+10.30-10.30-0.10x=15.25-10.30 collect like terms
0.15x=4.95 divide both sides by 0.15
x=33---------------number of quarters
103-x=103-33=70------------------number of dimes
CK
33*0.25+70*0.10=15.25
8.25+7.00=15.25
15.25=15.25

Hope this helps---ptaylor

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