SOLUTION: there were 24 nickles, dimes, and quarters whose total value equaled $4.25. how many coins of each kind were there if the number of nickels equaled the number of dimes?

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Question 1179758: there were 24 nickles, dimes, and quarters whose total value equaled $4.25. how many coins of each kind were there if the number of nickels equaled the number of dimes?
Found 3 solutions by mananth, greenestamps, josgarithmetic:
Answer by mananth(16946)   (Show Source):
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there were 24 nickles, dimes, and quarters whose total value equaled $4.25.
n+d+q=24
5n+10d+25q= 425
n=d

n+d+q=24
d+d+q=24
2d+q=24
5n+10d+25q= 425
5d+10d+25q=425
15d+25q =425
d dimes
q quarters

2.00 d + 1.00 q = 24.00

15.00 d + 25.00 q = 425.00 .............2
Eliminate q
multiply (1)by -25.00
Multiply (2) by 1.00
-50.00 d -25.00 q = -600.00
15.00 d 25.00 q = 425.00
Add the two equations
-35.00 d = -175.00
/ -35.00
d = 5.00
plug value of d in (1)
2.00 d + 1.00 q = 24.00
10.00 + 1.00 q = 24.00
1.00 q = 14.00
q = 14.00
Ans d = 5
q = 14
5 dimes
14 quarters

Answer by greenestamps(13203)   (Show Source):
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Let x = # of nickels
Then x = # of dimes (same as the number of nickels)
And then 24-2x = # of quarters (the total number of coins is 24)

The total value of the coins is $4.25, or 425 cents:

ANSWERS:
nickels: x = 5
dimes: x = 5
quarters: 24-2x=14

CHECK: 5(5)+10(5)+25(14)=25+50+350=425

Answer by josgarithmetic(39625)   (Show Source):
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how many coins of each kind were there if the number of nickels equaled the number of dimes?
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x nickels and x dimes,

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